Question 1204286:  Assume 𝛼 is opposite side a, 𝛽 is opposite side b, and 𝛾 is opposite side c. Solve the triangle, if possible. Round your answers to the nearest tenth. (If not possible, enter IMPOSSIBLE.) 
𝛼 = 36°, 𝛾 = 62°, a = 20 
 Found 2 solutions by  math_tutor2020, MathTherapy: Answer by math_tutor2020(3817)      (Show Source): 
You can  put this solution on YOUR website!  
𝛼 = Greek letter alpha (lowercase) 
𝛽 = Greek letter beta (lowercase) 
𝛾 = Greek letter gamma (lowercase)
 
 
𝛼 = 36° 
𝛽 = unknown 
𝛾 = 62°
 
 
𝛼 + 𝛽 + 𝛾 = 180  
36 + 𝛽 + 62 = 180  
98 + 𝛽 = 180  
𝛽 = 180 - 98 
𝛽 = 82°
 
 
Sides 
a = 20 
b = unknown 
c = unknown
 
 
Angles 
𝛼 = 36° 
𝛽 = 82° 
𝛾 = 62°
 
 
Law of Sines 
sin(𝛼)/a = sin(𝛽)/b 
sin(36)/20 = sin(82)/b 
b*sin(36) = 20*sin(82) 
b = 20*sin(82)/sin(36) 
b = 33.6948933264092 approximately 
b = 33.7 
Please make sure your calculator is set to degree mode.
 
 
Also, 
sin(𝛼)/a = sin(𝛾)/c 
sin(36)/20 = sin(62)/c 
c*sin(36) = 20*sin(62) 
c = 20*sin(62)/sin(36) 
c = 30.0432033439173 approximately 
c = 30.0
 
 
 
The fully solved triangle is 
𝛼 = 36° 
𝛽 = 82° 
𝛾 = 62° 
a = 20 
b = 33.7 
c = 30.0 
Diagram 
  
Only one unique triangle is possible due to the AAS congruence theorem. 
 
 Answer by MathTherapy(10557)      (Show Source): 
You can  put this solution on YOUR website! 
Assume 𝛼 is opposite side a, 𝛽 is opposite side b, and 𝛾 is opposite side c. Solve the triangle, if possible. Round your answers to the nearest tenth. (If not possible, enter IMPOSSIBLE.)
𝛼 = 36°, 𝛾 = 62°, a = 20
With 𝛼, or ∡A being 36°, 𝛾, or ∡C being 62°, then 𝛽, or ∡B = 82° [180° - (36° + 62°)]
Using the Law of sines, we get:  
Finding side b (opposite 𝛽), we get:  
                                 b * sin (36o) = 20 * sin (82o) ---- Cross-multiplying
                                     Side  
Finding side c (opposite 𝛾), we get:  
                                 c * sin (36o) = 20 * sin (62o) ---- Cross-multiplying
                                     Side  
Only when 2 sides and one angle are given (SSA or ASS: The famous/infamous DONKEY THEOREM), does the AMBIGUOUS case come into effect. The AMBIGUOUS case involves determining whether ONE or TWO triangles can be formed, based on the given 
information. However, when 2 angles and one side are given (AAS or ASA) - as in THIS CASE - then ONLY ONE (1) triangle
can be formed.  
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