Question 1204285: With each stroke, a pump removes  of the air in a container. After 6 strokes, what is the fraction of the original amount of air in the container that is left?
Found 3 solutions by ikleyn, MathLover1, math_tutor2020:
Answer by ikleyn(52848)   (Show Source):
You can put this solution on YOUR website! .
After 1st stroke, 5/6 of the initial air mass remains;
After 2nd stroke,  of the initial air mass remains;
After 3rd stroke,  of the initial air mass remains;
After 4th stroke,  of the initial air mass remains;
After 5th stroke,  of the initial air mass remains;
After 6th stroke,  of the initial air mass remains, or 0.3349 of the initial air mass remains (rounded). ANSWER
Solved.
For similar (TWIN) solved problems, see the links
https://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.1097807.html
https://www.algebra.com/algebra/homework/Sequences-and-series/Sequences-and-series.faq.question.75801.html
at this forum.
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Regarding the post by @MathLover1, I recall this medical proverb:
a drop of nicotine kills a horse.
Likewise, @MatnLover1's answer may kill a reader.
He will die if not from horror to have such a " tutor ", then from laughter.
So, for safety of your mind, you better ignore her post.
Answer by MathLover1(20850)  (Show Source):
Answer by math_tutor2020(3817)  (Show Source):
You can put this solution on YOUR website!
Answer: 15625/46656
Which is the same as writing 
How to get that answer:
With one stroke, 1/6 of the air is removed, so 5/6 of the air remains.
Do this 6 times to get (5/6)^6 = (5^6)/(6^6) = 15625/46656
When converting to decimal form,
15625/46656 = 0.3349 = 33.49% approximately
Roughly 33.49% of the original air remains inside the container.
Personally I think a percentage is the best way to represent the final answer, but you should stick to the fraction form since that's what the instructions state.
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