SOLUTION: A​ solid-gold jewelry box was found in the underwater palace of Cleopatra just off the shore of Treasure City. The length of the rectangular box is 25 centimeters less than tripl

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Question 1204255: A​ solid-gold jewelry box was found in the underwater palace of Cleopatra just off the shore of Treasure City. The length of the rectangular box is 25 centimeters less than triple the width. The perimeter of the box is 250 centimeters. Find the length and width of​ Cleopatra's solid-gold jewelry box.
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
The length of the rectangular box is 25 centimeters less than triple the width.
L=3W-25.......eq.1
The perimeter of the box is 250+centimeters.
2%28L%2BW%29=250.....eq.2
substitute the length from eq.1
2%283W-25%2BW%29=250
6W-50%2B2W=250
8W=250%2B50
8W=300
W=300%2F8
W=37.5
go to
L=3W-25.......eq.1, substitute W
L=3%2A37.5-25
L=87.5
the length and width of​ Cleopatra's solid-gold jewelry box is 87.5cm


Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.

For future readers of this post:

Do not take this problem seriously, since it INTENTLY uses inconsistent words and terms
as a perimeter for a 3D box (which is undetermined notion in Math) and also assumes
that 3D box has no third dimension, like height.

It is OBVIOUS that a person who created it, is mathematically illiterate
and composes such problems with the only one goal to prove how smart he is
by confusing and perplexing the readers.

Such problems give NOTHING for mathematical development of readers;
THEREFORE, do not spend your time for this GIBBERISH.