SOLUTION: Bill's bike wheels have a 26-in. diameter. The odometer on his bike counts the number of times a wheel rotates during a trip. If the odometer counts 200 rotations during the trip f
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Question 1204230: Bill's bike wheels have a 26-in. diameter. The odometer on his bike counts the number of times a wheel rotates during a trip. If the odometer counts 200 rotations during the trip from Bill's house to school, how many feet does Bill travel? Round to the nearest foot. Found 4 solutions by josgarithmetic, MathLover1, math_tutor2020, ikleyn:Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! given:
diameter
One rotation is same distance as:
Total distance traveled:
If the odometer counts rotations, we have
d = diameter = 26 inches
C = circumference = perimeter around the circle
C = pi*d
C = 3.14*26
C = 81.64
This is the approximate distance around the wheel. It's approximate because pi = 3.14 is approximate.
Use more decimal digits of pi to get a better approximation.
1 full rotation of the wheel will move the bike forward roughly 81.64 inches.
This assumes that there isn't any slipping. Slipping is when the wheel spins some amount different compared to how the bike moves. Example: the wheel rotates 5 feet but the bike only would move forward 2 feet.
200 such rotations would move the bike forward 200*81.64 = 16,328 inches.
Divide by 12 to go from inches to feet
16328/12 = 1,360.66666666667 approximately
When rounding to the nearest foot we get 1361 feet as the final answer.
As a shortcut, we can type this into the calculator
pi*26*200/12
where we let the calculator handle the decimal digits of pi for the best accuracy possible.
The result of which is approximately 1,361.35681655558 which rounds to 1361 feet
Either way we'll get the same answer.
Side note: 1361 ft = 1361/5280 = 0.2578 miles approximately