SOLUTION: Write the equation of the ellipse that has a center at (5,-4), a vertex at (12,-4), and a covertex at (5,-6).

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Question 1204200: Write the equation of the ellipse that has a center at (5,-4), a vertex at (12,-4), and a covertex at (5,-6).
Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52866) About Me  (Show Source):
You can put this solution on YOUR website!
.

The center is given - hence, all you need is to find semi-axes.

Find them from the given information.



Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
The standard form of the equation of an ellipse with center
(+h, +k) and major axis parallel to the +x-axis is
+%28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1
where
+a%3Eb
the length of the major axis is +2a
the coordinates of the vertices are (++h+±a, +k)
the length of the minor axis is++2b
the coordinates of the co-vertices are (++h,++k ±b)
the coordinates of the foci are (++h ± c, +k), where c%5E2=a%5E2-b%5E2
the ellipse that has
a center at (+5,+-4)

Thus, +h=5, +k=-4
vertex at (+12,+-4)=> (+5 ± +a,+-4)=>
+5%2Ba=12
+a=12-5
+a=7
a covertex at (+5,+-6)=>(+5,+-4±+b)
+-4%2Bb=-6
+b=6-4
+b=2
your ellipse is
+%28x-5%29%5E2%2F7%5E2%2B%28y-%28-4%29%29%5E2%2F2%5E2=1
+%28x-5%29%5E2%2F49%2B%28y%2B4%29%5E2%2F4=1