SOLUTION: An investor bought 300 shares of stock, some at $2.00 per share and some at $3.25 per share. If the total cost was $756.25, how many shares of each stock did the investor buy? (Rou

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: An investor bought 300 shares of stock, some at $2.00 per share and some at $3.25 per share. If the total cost was $756.25, how many shares of each stock did the investor buy? (Rou      Log On


   

Question 1204128: An investor bought 300 shares of stock, some at $2.00 per share and some at $3.25 per share. If the total cost was $756.25, how many shares of each stock did the investor buy? (Round to two decimal places if necessary.)
Found 2 solutions by mananth, MathLover1:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!

Let number of shares at $2.00 be x
And number of shares at $3,25 be y
The investor bought 300 shares of stock,
So, x+y = 300.....................................................(1)
Investment
the total cost was $756.25,
2x+3.25y = 756.25..............................................(2)
Now x+y = 300 multiply by 2
2x+2y = 600
2x+3.25y = 756.25 Subtract the equations ( From (2)
-1.25y = -156.25
divide by -1.25
y = -156.25/ -1.25
y =125
x = 300-125= 175
So, the investor bought 175 shares at $2.00 per share and 125 shares at $3.25 per share.

CHECK
175*2+3.25*125 =756.25



Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!


let shares ( $2.00 per share ) be x and shares ( $3.25 per share ) be y
if an investor bought 300 shares, we have
x%2By=300...solve for x
x=300-y......eq.1

If the total cost was $756.25, we have
2.00x%2B3.25y=756.25....eq.2
substitute x from eq.1
2.00%28300-y%29%2B3.25y=756.25
600-2.00y%2B3.25y=756.25
1.25y=756.25-600
1.25y=156.25
y=156.25%2F1.25
y=15625%2F125
y=125

go to eq.1 and substitute y
x=300-125......eq.1
x=175
check:
175%2A2.00%2B125%2A3.25=756.25