SOLUTION: If tan(x) = −40/9 and x is in quadrant IV, with 0° ≤ x < 360°, find the exact values of the expressions without solving for x. (a) sin(x/2) (b) cos(x/2) (c) tan

Algebra ->  Trigonometry-basics -> SOLUTION: If tan(x) = −40/9 and x is in quadrant IV, with 0° ≤ x < 360°, find the exact values of the expressions without solving for x. (a) sin(x/2) (b) cos(x/2) (c) tan      Log On


   



Question 1204118: If tan(x) = −40/9 and x is in quadrant IV, with 0° ≤ x < 360°, find the exact values of the expressions without solving for x.
(a) sin(x/2)

(b) cos(x/2)

(c) tan(x/2)


Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52864) About Me  (Show Source):
You can put this solution on YOUR website!
.
If tan(x) = −40/9 and x is in quadrant IV, with 0° ≤ x < 360°, find the exact values of the expressions without solving for x.
(a) sin(x/2)
(b) cos(x/2)
(c) tan(x/2)
~~~~~~~~~~~~~~~~~~~~~~~~~~

If tan(x) = −40/9 and x is in quadrant IV, then it means that 

    the opposite leg is 40 units, the adjacent leg is 9 units and the hypotenuse is  sqrt%2840%5E2+%2B+9%5E2%29 = sqrt%281681%29 = 41 unit.

It implies that  cos(x) = 9%2F41.


Next, use the formulas for half argument


    sin%28x%2F2%29 = -sqrt%28%281+-+cos%28x%29%29%2F2%29 = -sqrt%28%281-9%2F41%29%2F2%29 = -sqrt%2816%2F41%29 = -4%2Fsqrt%2841%29;


    cos%28x%2F2%29 = sqrt%28%281+%2B+cos%28x%29%29%2F2%29 = sqrt%28%281%2B9%2F41%29%2F2%29 = sqrt%2825%2F41%29 = 5%2Fsqrt%2841%29;


    tan%28x%2F2%29 = -4%2F5.

Solved.



Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!


tan%28x%29+=+-40%2F9
tan%28x%29+=+sin%28x%29%2Fcos%28x%29
also,
tan%28x%29+=+opp%2Fadj
sin+%28x%29=+opp+%2F+hyp+
cos+%28x%29+=+adj+%2F+hyp
then opp%2Fadj=+-40%2F9+=> opp=-40, adj=9
=> hyp=sqrt%28%28-40%29%5E2%2B9%5E2%29=41

then
sin+%28x%29=+-40%2F+41
cos+%28x%29+=+9+%2F+41+

(a)
sin%28x%2F2%29
using Half Angle Formulas
sin+%28x%2F2%29+=sqrt+%28+%281+-+cos%28x%29%29+%2F+2+%29
sin+%28x%2F2%29+=+%28+%281+-%289+%2F+41%29%29+%2F+2+%29
sin+%28x%2F2%29+=+sqrt+%28+16%2F41+%29
sin+%28x%2F2%29+=++4%2Fsqrt+%28+41+%29 or sin+%28x%2F2%29+=++-+4%2Fsqrt+%28+41+%29
sin is negative in Q IV
sin+%28x%2F2%29+=+-+4%2Fsqrt+%28+41+%29


(b)
cos%28x%2F2%29
cos+%28x%2F2%29+=+sqrt+%28+%281+%2B+%289+%2F+41%29%29+%2F+2+%29

cos+%28x%2F2%29+=+sqrt+%28+%2850%2F41%29+%2F+2+%29+
cos+%28x%2F2%29+=+sqrt+%28+25%2F41+%29+
cos+%28x%2F2%29+=+5%2Fsqrt%2841%29...cos is positive in Q IV


(c)
tan%28x%2F2%29=-%284%2Fsqrt+%28+41+%29%29%2F%285%2F+sqrt%2841%29%29=-4%2F5