|
Question 1204106: A line has a slope of -2/3
and passes through the point (9, 0). Write its equation in slope-
intercept form.
Write your answer using integers, proper fractions, and improper fractions in simplest form.
Found 3 solutions by mananth, josgarithmetic, greenestamps:
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! A line has a slope of -2/3
and passes through the point (9, 0). Write its equation in slope-
intercept form.
Write your answer using integers, proper fractions, and improper fractions in simplest form.
The general equation of line with a point and slope is given by
y-y1=m(x-x1) whwre m is the slope and (x1,y1) is the point
A line has a slope of -2/3 and passes through the point (9, 0).
y-0= -(2/3) (x-9)
y = -(2/3)x-(2/3)*-9
y = -(2/3)x +6 is the required equation
Answer by josgarithmetic(39621)  (Show Source):
You can put this solution on YOUR website! Slope Intercept Form, y=mx+b;
Point (9,0) and slope 
You can start in point-slope form and solve for "y".
OR,
y-mx=b, simple one-step FROM slope-intercept form.
 , and just simplify.
Answer by greenestamps(13203)  (Show Source):
You can put this solution on YOUR website!
You should understand how to use formal algebra to find the answer, as the other tutors did.
But you can get a better understanding of the topic by working the problem informally.
You are given that the slope is -2/3, so to write the equation in slope-intercept form you only need to find the y-intercept.
The given point is (9,0). To get from there to the y-axis, you need to move 9 units to the left.
With a slope of -2/3, in moving 9 units to the left you will move 6 units (2/3 of 9) up -- so the y value where you end up is +6 from the y value where you started, which was 0. So the y value where you end up -- which is the y-intercept -- is 0+6 = 6.
Then you have both the slope -2/3 and the y-intercept 6; the equation is
ANSWER: y = (-2/3)x+6
|
|
|
| |
