SOLUTION: How do you factor 6x^2+x-12=0. Could you please help me?

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Question 120407: How do you factor 6x^2+x-12=0. Could you please help me?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

6x%5E2%2Bx-12=0 Start with the given equation

%282x%2B3%29%283x-4%29=0 Factor the left side (note: if you need help with factoring, check out this solver)



Now set each factor equal to zero:
2x%2B3=0 or 3x-4=0

x=-3%2F2 or x=4%2F3 Now solve for x in each case


So our answer is
x=-3%2F2 or x=4%2F3


Notice if we graph y=6x%5E2%2Bx-12 we can see that the roots are x=-3%2F2 and x=4%2F3 . So this visually verifies our answer.


+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C0%2C+6x%5E2%2Bx-12%29+