SOLUTION: We are planning a reception for our daughter. The hall that we are renting charges a $55 cleanup fee. In addition to the cleanup fee, they charge $27 per guest for food and drinks.

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Question 1203896: We are planning a reception for our daughter. The hall that we are renting charges a $55 cleanup fee. In addition to the cleanup fee, they charge $27 per guest for food and drinks.
If we have $2,600.00 available, what is the maximum number of guest we can invite without going over our budget?

Found 2 solutions by ankor@dixie-net.com, MathLover1:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The hall that we are renting charges a $55 cleanup fee.
In addition to the cleanup fee, they charge $27 per guest for food and drinks.
If we have $2,600.00 available, what is the maximum number of guest we can invite without going over our budget?
:
let g = no. of guests
27g + 55 = 2600
27g = 2600 - 55
27g = 2545
g = 2545/27
g = 94 guests, low integer is all we want here
:
check: (27*94) + 55 = $2593, $7 under budget

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

let the number of guest be x
charge $27 per guest for food and drinks
y=27x%2Bb
$b=55 cleanup fee
y=27x%2B55
if we have $2600.00 available,
2600.00=27x%2B55
2600.00-55=27x
2545=27x
x=2545%2F27
x=94.25925925925925
x=94 is the maximum number of guest we can invite without going over our budget