SOLUTION: Write the equation of the line that passes through the point (6,-8) and has a slope 4.

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Question 1203835: Write the equation of the line that passes through the point (6,-8) and has a slope 4.
Found 3 solutions by math_tutor2020, MathLover1, kiks:
Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

m = 4 = slope
(x1,y1) = (6,-8) = point we want the line to pass through

y - y1 = m(x - x1) ...... point slope form
y - (-8) = 4(x - 6)
y + 8 = 4x - 24
y = 4x - 24 - 8
y = 4x - 32 is the final answer (in slope-intercept form anyway).

Check:
Plug in x = 6 and we should arrive at y = -8
y = 4x - 32
y = 4*6 - 32
y = 24 - 32
y = -8
We have shown the point (6,-8) is on the line y = 4x-32.
Everything checks out.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

the equation of the line that passes through the point (6,-8) and has a slope 4
use point slope formula
y-y%5B1%5D=m%28x-x%5B1%5D%29
substitute given data
y-%28-8%29=4%28x-6%29
y%2B8=4x-24
y=4x-24-8
y=4x-32




Answer by kiks(2) About Me  (Show Source):
You can put this solution on YOUR website!
Using the point gradient formula: y-y1=m(x-x1)
Sub the gradient into 'm; and the points into 'y1' and 'x1'.
hence
y+8=4(x-6)
y+8=4x-24
y=4x-32