SOLUTION: The length of a rectangle is 3 less than twice the width. The perimeter is 36. Find the dimensions of the rectangle.

Algebra ->  Human-and-algebraic-language -> SOLUTION: The length of a rectangle is 3 less than twice the width. The perimeter is 36. Find the dimensions of the rectangle.       Log On


   

Question 1203746: The length of a rectangle is 3 less than twice the width. The perimeter is 36. Find the dimensions of the rectangle.
Found 2 solutions by ikleyn, Theo:
Answer by ikleyn(52851) About Me  (Show Source):
You can put this solution on YOUR website!
.

w + (2w-3) = 36/2

3w - 3 = 18

3w = 18 + 3

3w = 21

 w = 21/3 = 7.


ANSWER.  The dimensions of the rectangle are 7 and 2*7 -3 = 11.


CHECK.  7 + 11 + 7 + 11 = 36   ! correct !

Solved.



Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
P = 2L + 2W
L = 2W - 3
P = 2 * (2W - 3) + 2W = 4W - 6 + 2W = 6W - 6
P = 36
36 = 6W - 6
add 6 to both sides to get:
42 = 6W
solve for W to get:
W = 7
L = 2W - 3 = 14 - 3 = 11
you have:
L = 11
W = 7
P = 2L + 2W = 22 + 14 = 36
solution is confirmed to be good.
P = the perimeter of the rectangle
L = the length of the rectangle.
W = the width of the rectangle.