SOLUTION: In 2004 a city department bought 500 dozen pencils at 40 cents per dozen. In 2007, only 75% as many pencils were bought in 2004, but the price was 20% higher than the 2004 price.

Algebra ->  Matrices-and-determiminant -> SOLUTION: In 2004 a city department bought 500 dozen pencils at 40 cents per dozen. In 2007, only 75% as many pencils were bought in 2004, but the price was 20% higher than the 2004 price.       Log On


   



Question 1203580: In 2004 a city department bought 500 dozen pencils at 40 cents per dozen. In 2007, only 75% as many pencils were bought in 2004, but the price was 20% higher than the 2004 price. The total cost of the pencils bought in 2007 was
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52884) About Me  (Show Source):
You can put this solution on YOUR website!
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In 2004 a city department bought 500 dozen pencils at 40 cents per dozen.
In 2007, only 75% as many pencils were bought highlight%28as%29 in 2004,
but the price was 20% higher than the 2004 price.
The total cost of the pencils bought in 2007 was
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According to the problem, in 2007  0.75*500 dozens of pencils was bought, i.e. 375 dozen.

The price in 2007 was 1.2*40 cents per dozen, or 48 cents per dozen.


So, the answer to the problem's question is this product 48*375 = 18000 cents, or 180 dollars.

Solved.


This problem teaches us to very important skills, which is to multiply numbers correctly.



Answer by greenestamps(13209) About Me  (Show Source):
You can put this solution on YOUR website!


The total cost in 2004 was 500($0.40) = $200.

In 2007 the number of pencils was 75% as much as in 2004. That will reduce the total cost by a factor of 75/100 = 3/4.

The price was 20% higher in 2007 than in 2004. That will increase the total cost by a factor of 120/100 = 6/5.

So the total cost in 2007 was $200, multiplied by (3/4)(6/5) = 18/20 = 9/10.

(9/10)($200)=$180.

ANSWER: $180