SOLUTION: find the probability distribution and distribution function for the numbers of head when 3 balanced coins are tossed

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Question 1203531: find the probability distribution and distribution function for the numbers of head when 3 balanced coins are tossed


Found 2 solutions by math_helper, ikleyn:
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

Using C(n,r) = n!/((n-r)!r!) below...

There are +2%5E3+=+8+ outcomes possible. So 8 will be the denominator.
How many outcomes have 0 heads? 1 (TTT)
How many outcomes have 1 head? C(3,1) = 3 (HTT, THT, TTH)
How many outcomes have 2 heads? C(3,2) = 3 (HHT, HTH, THH)
How many outcomes have 3 heads? C(3,3) = 1 (HHH)

Thus the distribution is:
0 heads: 1/8
1 head: 3/8
2 heads: 3/8
3 heads: 1/8
(Note they sum to 8/8 = 1, which is expected since one of these outcomes must occur)
The function notation is P(r heads) = +C%283%2Cr%29%2F8++, 0%3C=r%3C=3

Answer by ikleyn(52930) About Me  (Show Source):
You can put this solution on YOUR website!
.
find the probability distribution and distribution function
for the numbers of head when 3 balanced coins are tossed
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These words  " probability distribution "  and  " distribution function "  mean the same:
they denote the same conception.   In other words,  they are synonyms.

Therefore, in your post there is no need to ask twice about the same thing.
To ask once is just quite enough.


Being too pathetic doesn't make your post better.
Asking twice, you demonstrate lack of knowledge on the subject.