Question 1203379: Hi
Leo and issac had 95 balls together. Leo gave away 3 more than issac. Issac was left with 5 fewer than the balls he gave away. Leo had 2 more balls left than issac. How many did Leo give away.
Thanks
Found 3 solutions by josgarithmetic, ikleyn, greenestamps: Answer by josgarithmetic(39623) (Show Source): Answer by ikleyn(52835) (Show Source):
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(a) Leo and issac had 95 balls together.
(b) Leo gave away 3 more than issac.
(c) Issac was left with 5 fewer than the balls he gave away.
(d) Leo had 2 more balls left than issac.
How many did Leo give away.
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x = Leo had initially
y = Issac had initially
z = Leo gave away
From (a), we have this equation x + y = 95. (1)
From (b), Issac gave away (z-3).
From (c), we have this equation y - (z-3) = ((z-3)-5), or y - 2z = -11 (2)
From (d), we have this equation x - z = y - (z-3) + 2, or x - y = 5 (3)
Thus, we have this system of equations
x + y = 95 (1)
y - 2z = -11 (2)
x - y = 5 (3)
Add equations (1) and (3). Get 2x = 100, x = 100/2 = 50. (Leo had initially)
Then from (1), y = 95 - x = 95 - 50 = 45. (Issac had initially)
Then from (2), 2z = y + 11 = 45 + 11 = 56, z = 56/2 = 28. (Leo gave away)
ANSWER. Leo gave away 28 balls.
CHECK. Issac gave away 28-3 = 25.
Issac was left with 45 - 25 = 20.
Leo was left with 50 - 28 = 22.
Leo left - Issac left = 22 - 20 = 2 (correct).
Solved.
Answer by greenestamps(13203) (Show Source):
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