SOLUTION: In the xy-plane, if a point with the coordinates (c, d) lies in the solution set of this system of inequalities, what is the minimum possible value of d? y>-4x + 540, y > 2x

Algebra ->  Inequalities -> SOLUTION: In the xy-plane, if a point with the coordinates (c, d) lies in the solution set of this system of inequalities, what is the minimum possible value of d? y>-4x + 540, y > 2x       Log On


   

Question 1203367: In the xy-plane, if a point with the coordinates (c, d) lies in the solution set of this system of inequalities,
what is the minimum possible value of d?
y>-4x + 540,
y > 2x
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


ANSWER (to the problem as presented): There is no minimum possible value of d.

y%3E-4x%2B540
y%3E2x

graph%28400%2C400%2C-20%2C120%2C-100%2C900%2C2x%2C-4x%2B540%29

Because both inequalities are strict inequalities, any solution to the pair of inequalities lies ABOVE both constraint boundary lines.

Solving the pair of equations of the constraint boundary lines, we find the point of intersection is (90,180).

So we know the minimum possible value of the y coordinate is GREATER THAN 180....

But there is no "minimum value greater than 180".

In order for it to be possible to answer the question, the inequalities must both be "greater than or equal to" instead of "greater than":

y%3E=-4x%2B540
y%3E=2x

Then we know the minimum value of d, the y coordinate: 180

ANSWER (to the corrected problem): 180