SOLUTION: A frustum of a sphere of radius 13 cm is formed by two parallel planes on opposite sides of the center, each at distance of 5 cm from the center. Determine the volume of the frustu

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Question 1203337: A frustum of a sphere of radius 13 cm is formed by two parallel planes on opposite sides of the center, each at distance of 5 cm from the center. Determine the volume of the frustum (a) by using the prismoidal rule, and (b) by using the formula for the volume of a frustum of a sphere
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A frustum of a sphere of radius 13 cm is formed by two parallel planes on opposite sides of the center, each at distance of 5 cm from the center. Determine the volume of the frustum (a) by using the prismoidal rule, and (b) by using the formula for the volume of a frustum of a sphere
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Find the volumes of the 2 segments NOT in the frustum:
For each:
V+=+pi%2Ah%5E2%2A%283r-h%29%2F3 where r = 13 and and h = 6.5-5 = 1.5
V+=+pi%2A64%2839-1.5%29%2F3+=+800pi for each
---> 1600pi
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Subtract that from the volume of the shpere:
---> 4%2Api%2A13%5E3%2F3+-+4800pi%2F3+=+2396%2Api cc
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h = the distance from the surface of the sphere to the plane on the diameter.
PS This is an equation used in the calculation of the volume of a liquid in a spherical tank where h would be the depth of the liquid.
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I mistakenly used 13 as the diameter when it's the radius.
The method is good, tho.
The student can redo it using 13 instead of 6.5

Answer by ikleyn(52810) About Me  (Show Source):
You can put this solution on YOUR website!
.

Alan, what is

        h = 6.5-5 = 1.5

in your solution ?


I want to ask,  what  " 6.5 "  does represent there ?


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Alan,  don't you think that  h  should be   h = 13-5 = 8 cm ?