SOLUTION: A brownie recipe requires one and one half cups of sugar to one cup of chocolate chips. If three and one half cups of sugar is used, what quantity of chocolate chips will be needed

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A brownie recipe requires one and one half cups of sugar to one cup of chocolate chips. If three and one half cups of sugar is used, what quantity of chocolate chips will be needed      Log On


   



Question 1203237: A brownie recipe requires one and one half cups of sugar to one cup of chocolate chips. If three and one half cups of sugar is used, what quantity of chocolate chips will be needed, according to the recipe?
Found 3 solutions by greenestamps, Theo, josgarithmetic:
Answer by greenestamps(13209) About Me  (Show Source):
You can put this solution on YOUR website!


Write and solve a proportion showing that the ratio of sugar to chocolate chips is constant:

1.5%2F1=3.5%2Fx
1.5x=3.5
x=3.5%2F1.5=7%2F3

ANSWER: 7/3 cups, or 2 1/3 cups, of chocolate chips


Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
s/c = 1.5/1 = 3/2
you get s/c = 3/2
from that, you get s = 3/2 * c, or c = 2/3 * s
3.5 cups of sugar is equal to 3 and 1/2 which is equal to 7/2 cups of sugar.
c = 2/3 * s becomes c = 2/3 * 7/2 = 14/6 cups of chocolae chips.
14/6 = 2 and 2/6 cups of chocolate chips.
to confirm, multiply 2 and 2/6 by 1.5 to get 3 and 3/6 which is equal to 3.5 cups of sugar.
your solution is that you would need 2 and 1/3 cups of chocolate chips, which can also be shown as 7/3 cups of chocolate chips whiich.
in decimal form, that would be equal to 2.33 cups of chocolate chips, when rounded to 2 decimal places.

Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
                          CUPS, recipe          CUPS, BATCH

Sugar                      1.5                   3.5

Chocolate Chips            1.0                   c

Setup as proportion if you want; but, look, think:

c=1%2A%283.5%2F1.5%29
Compute this for c.

or also try
c=3.5%2F1.5=35%2F15=%285%2A7%29%2F%285%2A3%29=7%2F3

c=2%261%2F3