SOLUTION: Barry has a bag of marbles. 3/8 of the marbles are red. 70% of the remaining marbles are yellow. The other 12 marbles are green. How many marbles are there in the bag altogether?
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-> SOLUTION: Barry has a bag of marbles. 3/8 of the marbles are red. 70% of the remaining marbles are yellow. The other 12 marbles are green. How many marbles are there in the bag altogether?
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Question 1203168: Barry has a bag of marbles. 3/8 of the marbles are red. 70% of the remaining marbles are yellow. The other 12 marbles are green. How many marbles are there in the bag altogether? Found 2 solutions by ikleyn, greenestamps:Answer by ikleyn(52798) (Show Source):
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Barry has a bag of marbles. 3/8 of the marbles are red.
70% of the remaining marbles are yellow. The other 12 marbles are green.
How many marbles are there in the bag altogether?
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Let x be the total marbles (altogether).
Write equation for total marbles
+ + 12 = x.
To solve, multiply all the terms by 8; then simplify
3x + 0.7*5x + 96 = 8x
3x + 3.5x + 96 = 8x
96 = 8x - 3x - 3.5x
96 = 1.5x
x = 96/1.5 = 64.
ANSWER. There are 64 marbles in the bag.
Given that 3/8 of the marbles are red, let 8x be the total number of marbles and 3x be the number of red marbles. Then the number of marbles of other colors is 8x-3x = 5x.
70% of the remaining marbles are yellow. 70% of 5x is 0.7(5x) = 3.5x.
The total number of red and yellow marbles is 3x+3.5x = 6.5x; the total number of marbles is 8x. So the number of green marbles is 8x-6.5x = 1.5x.
The number of green marbles is 12:
1.5x = 12
x = 12/1.5 = 8
ANSWER: The total number of marbles in the bag is 8x = 64