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Question 1203122: I have attached a file for the question paper. I cannot do the last question. The markscheme only has the answers, not working, so I don't understand how to do the last question (question 17)
https://www.11plusguide.com/wp-content/uploads/2019/01/Maths-Paper-2015-Entry-CSSE.pdf
Please help!!
Thanks
Found 2 solutions by Theo, greenestamps:
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! i get x = 2 because you have a vertical line at x = 2, therefore all points on that line have x = 2.
the two points shown on that vertical line are (2,5) ande (2,15).
i get y = 15 as follows:
the slope of the line is equal to the change in y divided by the corresponding change in x.\
the two points you can use are:
(0,0) and (2,5)
the slope is (5-0) / (2-0) = 5/2.
any two points on that line will generate the same slope.
the other two points are (2,5) and (6,y)
the slope is 5/2, therefore you get (y-5) / (6-2) = 5/2.
simplify to get (y-5) / 4 = 5 / 2
multiply both sides of that equation by 4 to get:
y - 5 = 4 * 5 / 2 which becomes:
y - 5 = 10
add 5 to both sides of that equation to get:
y = 15.
your solution for this problem should be x = 2 and y = 15.
i graphed the equation for that line so you can see it better.
the equation is y = 5/2 * x
when x = 2, y = 5/2 * 2 = 5
when x = 6, y = 5/2 * 6 = 15
here's the graph.
as a bonus, you get:
when y = 12, the equation becomes 12 = 5/2 * x
solve for x to get x = 2/5 * 12 = 24/5 = 4.8, as shown on the graph.
Answer by greenestamps(13203)  (Show Source):
You can put this solution on YOUR website!
The level of the questions on the test show that it is a test for rather young students. In that case, probably the answers provided in the response from the other tutor can be considered valid.
Note, however, that technically the problem as shown is invalid; the answers that are apparently expected assume that the horizontal and vertical dotted lines are in fact horizontal and vertical, and that the diagonal dotted line passes through the origin. But the information provided on the test does not tell us those things....
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