SOLUTION: triangle CDE exists such that D=90 degrees. Given that CD=2.51cm and DE=2.46cm, what is the length of CE?

Algebra ->  Triangles -> SOLUTION: triangle CDE exists such that D=90 degrees. Given that CD=2.51cm and DE=2.46cm, what is the length of CE?      Log On


   

Question 1203090: triangle CDE exists such that D=90 degrees. Given that CD=2.51cm and DE=2.46cm, what is the length of CE?
Found 4 solutions by Alan3354, josgarithmetic, math_tutor2020, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
triangle CDE exists such that D=90 degrees. Given that CD=2.51cm and DE=2.46cm, what is the length of CE?
----------------------
It's a right triangle.
Use Pythagoras.

Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
Even without drawing the figure, some thought should lead you to DE is the hypotenuse. The legs are CD and EC.

Pythagorean Theorem CD%5E2%2BDE%5E2=CE%5E2;
fill-in what you know and solve what you need.

Answer by math_tutor2020(3816) About Me  (Show Source):
You can put this solution on YOUR website!



We have a right triangle, so we'll use the pythagorean theorem.
%28leg1%29%5E2%2B%28leg2%29%5E2+=+%28hypotenuse%29%5E2

%28CD%29%5E2+%2B+%28DE%29%5E2+=+%28CE%29%5E2

CE+=+sqrt%28%28CD%29%5E2+%2B+%28DE%29%5E2%29
I'll let the student finish up.

Answer by ikleyn(52754) About Me  (Show Source):
You can put this solution on YOUR website!
.

It is more than obvious.