Question 1202743: A sack filled with marbles contains:
17 red marbles numbered 1 to 17
35 blue marbles numbered 1 to 35
42 green marbles numbered 1 to 42
13 yellow marbles numbered 1 to 13
The answer should be entered as a decimal and if necessary, round to at least four decimal places.
If you randomly pull one marble out of the sack, set it aside, then pull a second marble, what is the probability of drawing a yellow marble followed by a green marble?
Answer by math_tutor2020(3817)   (Show Source):
You can put this solution on YOUR website!
The numbers on the marbles appear to be a distraction.
A = marble is yellow on 1st selection
B = marble is green on 2nd selection
P(A) = (13 yellow)/(17+35+42+13 total)
P(A) = 13/107
P(B given A) = probability B happens given we know A happened
P(B given A) = (42 green)/(107-1 remaining)
P(B given A) = 42/106
P(B given A) = 21/53
P(A and B) = P(A)*P(B given A)
P(A and B) = (13/107)*(21/53)
P(A and B) = 0.04813965790866
P(A and B) = 0.0481
Answer: 0.0481 (approximate)
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