SOLUTION: Solve equation, sin(2x) - sinx - 2cosx + 1 = 0, on the interval 0 < or equal x < 2pi.

Algebra ->  Trigonometry-basics -> SOLUTION: Solve equation, sin(2x) - sinx - 2cosx + 1 = 0, on the interval 0 < or equal x < 2pi.      Log On


   

Question 1202699: Solve equation, sin(2x) - sinx - 2cosx + 1 = 0, on the interval 0 < or equal x < 2pi.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
This is 2 sin x cos x-sinx -2cos x+1=0=sin x(2 cos x-1)-(2 cos x-1)=0
this is (sin x-1)(2cos x-1)=0
sin x=1 and cos x=1/2
This is at pi/3, pi/2, and 5pi/3 or 1.05, 1.57, 5.23