SOLUTION: The weight of a body on or above the surface of the earth varies inversely with the square of the distance from the body to the center of the earth. If a body weighs 25,000 pounds

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: The weight of a body on or above the surface of the earth varies inversely with the square of the distance from the body to the center of the earth. If a body weighs 25,000 pounds      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1202545: The weight of a body on or above the surface of the earth varies inversely with the square of the distance from the body to the center of the earth. If a body weighs 25,000 pounds at a distance of 100,000 miles from the center of the earth, how much would it weigh 5000 miles from the center of the earth?
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
something like this one, two or three days ago

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


The second distance is 5000/100000 = 1/20 of the first distance. Since the variation is inversely as the square of the distance, the second weight is 20^2 = 400 times the first weight.

ANSWER: 25,000 * 400 = 10,000,000 pounds