SOLUTION: The express train made the trip in 20 hours. The freight train took 25 hours because it was 10 miles per hour slower than the express train. What was the speed of each train?
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Question 1202491: The express train made the trip in 20 hours. The freight train took 25 hours because it was 10 miles per hour slower than the express train. What was the speed of each train? Found 3 solutions by Theo, josgarithmetic, greenestamps:Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! rate * time = distance
express train made the trip in 20 hours.
equation for express train is r * 20 = d
r is the rate
d is the distance
the freight train took 25 hours because it was 10 miles per hour slower than the exptress.
equation for freight train is (r - 10) * 25 = d
simplify the second equation and leave the first eqution as is to get:
r * 20 = d
r * 25 - 250 = d
subtract the first equation from the second to get:
5 * r - 250 = 0
add 250 to both sides of the equation the solve for r to get:
5 * r = 250 resulting in r = 50
this suggests that the express was traveling at 50 miles per hour and the freight train was traveling at 40 miles per hour.
equation become:
50 * 20 = d
40 * 25 = d
solve for d in both equaations to get d = 1000 in each equation.
solutuion is that the speed of the express train was 50 miles per hour and the speed of the freight train was 40 miles per hour.