SOLUTION: The second and fifth terms are in a geometric progression are 12 and 40.5 respectively. Find the first term and the common ratio. Hence, write down an expression for the nth term.
Algebra ->
Test
-> SOLUTION: The second and fifth terms are in a geometric progression are 12 and 40.5 respectively. Find the first term and the common ratio. Hence, write down an expression for the nth term.
Log On
Question 1202406: The second and fifth terms are in a geometric progression are 12 and 40.5 respectively. Find the first term and the common ratio. Hence, write down an expression for the nth term. Found 3 solutions by greenestamps, ikleyn, mananth:Answer by greenestamps(13216) (Show Source):
You can put this solution on YOUR website! .
The second and fifth terms in a geometric progression are 12 and 40.5 respectively.
Find the first term and the common ratio. Hence, write down an expression for the nth term.
~~~~~~~~~~~~~~~~~~~~~~
Write the terms in standard form
= a*r, = ,
Take the ratio
= = = = 3.375.
It implies r = = 1.5.
Thus the common ratio is r= 1.5.
Now the first term is a = = = 8.
The expression for the n-th term is = = .
You can put this solution on YOUR website! The second and fifth terms are in a geometric progression are 12 and 40.5 respectively. Find the first term and the common ratio. Hence, write down an expression for the nth term.
nth term of a GP is an=ar^(n-1)
2nd term
a2 = a*r^(2-1)
12= a*r
5th term
40.5= a*r^(5-1)
40.5 = ar^4
40.5= ar*r^3
40.5 = 12*r^3 (ar=12)
40.5/12 = r^3
3.375=r^3
3 15/40=r^3
135/40 =r^3
27/8 =r^3
cube root
r= 3/2
ar= 12
r = 3/2
a*3/2=12
a=8
an = a*r^(n-1)
an = 8*3/2 ^(n-1)