Question 1202196:  Determine the equation of a cosine function for the following graph of a sinusoidal function: 
https://gyazo.com/80871eaf3fe6163e135f3fbce5538d74
 
 
 Found 2 solutions by  ikleyn, math_tutor2020: Answer by ikleyn(52903)      (Show Source):  Answer by math_tutor2020(3817)      (Show Source): 
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Answer: y = 2.5*cos(2x)-1 
This is when you are in degree mode.
 
 
 
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Explanation:
 
 
The image from the question is this 
 
 
 
The template for cosine is  
y = A*cos(B(x-C))+D
 
 
The variables are: 
|A| = amplitude 
B = helps determine the period, more on that later 
C = phase shift, which is the side to side shift 
D = up and down shift, useful to determine midline
 
 
The goal is to determine the values of A, B, C, and D.
 
 
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Let's start with A.
 
 
The amplitude is half of the height of the sine wave. 
The peak occurs when y = 1.5 and the valley is when y = -3.5; these represent the largest and smallest possible y values respectively.
 
 
Subtract and use absolute value to find the vertical distance between peak and valley. 
|peak - valley| = |1.5 - (-3.5)| 
|peak - valley| = |1.5 + 3.5| 
|peak - valley| = |5| 
|peak - valley| = 5
 
 
Or you could say 
|valley - peak| = |-3.5 - 1.5| 
|valley - peak| = |-5| 
|valley - peak| = 5
 
 
The vertical distance from peak to valley is 5 units. 
Half of this is 5/2 = 2.5 and it is the amplitude.
 
 
|A| = 2.5 leads to either A = 2.5 or A = -2.5 
We use A = 2.5 because the cosine graph is above the x axis when x = 0.
 
 
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Now onto the variable B.
 
 
This variable is tied to the period. 
The period is the length of each cycle, aka wavelength.
 
 
One peak occurs at x = 0 
The next neighboring peak to the right is when x = 180 
This is a gap of 180-0 = 180 units 
The period is 180 because the curve repeats itself every 180 units.
 
 
T = 180 = period 
B = 2pi/T 
B = 2pi/180 
B = pi/90 
That would be the value of B if we are in radian mode.
 
 
However, the next set of steps show a much nicer result for B when in degree mode. 
B = 360/T 
B = 360/180 
B = 2
 
 
Because the x axis shows 90,180,270,etc it appears your teacher might want degree mode.
 
 
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The phase shift is C = 0 because cosine has x = 0 lead to a peak. We haven't shifted the peak left or right off the y axis. 
 
 
I recommend using a graphing tool like Desmos to look at y = cos(x) to see what I mean.  
GeoGebra is another handy graphing tool I use all the time.
 
 
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The midline is y = D to represent the horizontal line cutting through the middle of this cosine curve.
 
 
Apply the midpoint of the peak and valley 
(peak+valley)/2 = (1.5+(-3.5))/2 = -2/2 = -1
 
 
The midline is y = -1 and we get D = -1
 
 
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Summary  
A = 2.5 
B = 2 (when in degree mode) 
C = 0 
D = -1
 
 
Then 
y = A*cos(B(x-C))+D 
y = 2.5*cos(2(x-0))+(-1) 
y = 2.5*cos(2x)-1 
This is when your calculator is in degree mode.
 
 
Graph using Desmos 
https://www.desmos.com/calculator/ju2jkpfbkq 
 
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