SOLUTION: Two chords, AD and BC of a circle intersect at a point O inside the circle. Given that BO=5cm, OD=3cm and CD=3.6 cm, calculate the length AB

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Question 1202157: Two chords, AD and BC of a circle intersect at a point O inside the circle. Given that BO=5cm, OD=3cm and CD=3.6 cm, calculate the length AB
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
helpful article in case your book does not include it
https://en.wikipedia.org/wiki/Intersecting_chords_theorem

Answer by ikleyn(52797) About Me  (Show Source):
You can put this solution on YOUR website!
.
Two chords, AD and BC of a circle intersect at a point O inside the circle.
Given that BO = 5 cm, OD = 3 cm and CD = 3.6 cm, calculate the length AB.
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Make a sketch, drawing the circle, the chords and marking the points.


Consider triangles AOB and DOC.

These triangles are similar.


Indeed, their angles AOB and DOC are congruent, since they are vertical angles.

Angles BAO and OCD are congruent, too, because the angles BAD and BCD are inscribed angles
leaning on the same arc BD of the circle.


It is just enough for the proof that triangles AOB and DOC are similar, having two pairs 
of congruent angles.


From the triangle similarity, the corresponding pairs of sides are (BO,OD) and (AB,CD),
so we can write a proportion

    abs%28BO%29%2Fabs%28OD%29 = abs%28AB%29%2Fabs%28CD%29.


Substituting the values, we get

    5%2F3 = abs%28AB%29%2F3.6.


It gives  AB = %285%2A3.6%29%2F3 = 18%2F3 = 6.


ANSWER.  AB = 6 cm.

Solved.