SOLUTION: Assume that a sample is used to estimate a population proportion p. To find the 99% confidence interval for a sample of size 368 with 243 successes, you need to use which one the f

Algebra ->  Probability-and-statistics -> SOLUTION: Assume that a sample is used to estimate a population proportion p. To find the 99% confidence interval for a sample of size 368 with 243 successes, you need to use which one the f      Log On


   



Question 1202135: Assume that a sample is used to estimate a population proportion p. To find the 99% confidence interval for a sample of size 368 with 243 successes, you need to use which one the following calculator
Chi-Square Test for Independence
Two Independent Sample Means Comparison Given Statistics
One-Way ANOVA
Hypothesis Test for a Population Mean Given Statistics
Confidence Interval for a Population Mean Given Data
Chi-Square Test for Goodness of Fit
Two Independent Proportions Comparison
Confidence Interval for a Population Mean Given Statistics
Hypothesis Test for a Population Mean Given Data
Confidence Interval for a Population Proportion
Hypothesis Test for a Population Proportion
Two Dependent Sample Means Comparison Given Data
Two Independent Sample Means Comparison Given Data

Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places.
Confidence interval =

Express the same answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places.
< p <

Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Confidence Interval for a Population ProportionConfidence Interval for a Population Proportion
p hat is 243/368=0.6603
the half interval is z(0.995)*sqrt (p hat*(1- phat)/n)
half-interval Is 2.576*0.0247=00636
interval is (0.597, 0.724) and you can use that to make the tri-linear inequality.

Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.

Hello, @Boreal,

I am glad to see you returned back to the forum (!)


During your absence, I substituted you, solving here various statistics problems.