SOLUTION: PLease help me solve for the 3 different values of x. I came up with 9/3,1,0. Thank you. 18x^2-12x^3=0 Also, 9x^2-3x+0

Algebra ->  Expressions-with-variables -> SOLUTION: PLease help me solve for the 3 different values of x. I came up with 9/3,1,0. Thank you. 18x^2-12x^3=0 Also, 9x^2-3x+0      Log On


   

Question 120191: PLease help me solve for the 3 different values of x. I came up with 9/3,1,0.
Thank you. 18x^2-12x^3=0 Also, 9x^2-3x+0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
18x%5E2-12x%5E3=0 Start with the given equation

6x%5E2%283-2x%29=0 Factor out the GCF 6x%5E2



Now set each factor equal to zero:

6x%5E2=0 or 3-2x=0

Now solve for x for each factor:

x=0 or x=3%2F2 note: since the left term is squared, this means the zero occurs twice.

So the zeros of 18x%5E2-12x%5E3 are:

x=0 (with a multiplicity of 2) and x=3%2F2



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Is it supposed to read: 9x%5E2-3x=0?

9x%5E2-3x=0 Start with the given equation

3x%283x-1%29=0 Factor out the GCF 3x



Now set each factor equal to zero:

3x=0 or 3x-1=0

Now solve for x for each factor:

x=0 or x=1%2F3

So the zeros of 9x%5E2-3x are:


x=0 or x=1%2F3