SOLUTION: water is flowing through a pipe with radius 14 cm.The maximum depth of the water is 9 cm.What is the width,PQ,of the surface of the water?

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Question 1201828: water is flowing through a pipe with radius 14 cm.The maximum depth of the water is 9 cm.What is the width,PQ,of the surface of the water?
Found 2 solutions by math_tutor2020, ikleyn:
Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

Answer:
6*sqrt(5) centimeters exactly
6*sqrt(5) = 13.4164078649987 centimeters approximately
Round that approximate value however needed.


Work Shown:

This is what the diagram probably looks like

The diagram is not to scale.
The radius 14 cm is broken down into the pieces 5 cm and 9 cm.
The water's height is 9 cm, and the remaining 5 cm is the gap from the water line to the center of the circle.
The radius bisects the chord, meaning each smaller congruent piece is x cm long.

Apply the intersecting chords theorem
https://www.mathsisfun.com/geometry/circle-intersect-chords.html
and we get the following
a*b = c*d
x*x = 9*5
x^2 = 9*5
x = sqrt(9*5)
x = sqrt(9)*sqrt(5)
x = 3*sqrt(5)
Therefore,
2x = 2*3*sqrt(5) = 6*sqrt(5) represents the exact width of the water's surface when the max depth of the water is 9 cm.

6*sqrt(5) = 13.4164078649987 approximately.

Edit: I just realized I made a silly error. Refer to the solution by @ikleyn for the correct values to use in the intersecting chords theorem.

Answer by ikleyn(52847) About Me  (Show Source):
You can put this solution on YOUR website!
.
water is flowing through a pipe with radius 14 cm.The maximum depth of the water is 9 cm.
What is the width, PQ, of the surface of the water?
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        The solution by @math_tutor2020 is  INCORRECT.
        The error is in incorrect using the intersecting chords theorem.
        I came to bring a correct solution.
        My solution is in two different forms,  for better clarity.


                    Solution 1


In the post by math_tutor2020, you can see the right-angled triangle 
with the hypotenuse of 14 cm (the radius from the center to the point P or Q)
and one leg of 14-9 = 5 cm.

Hence, half of PQ is  sqrt%2814%5E2-5%5E2%29 = sqrt%28196-25%29 = sqrt%28171%29.


Then the segment PQ itself is  2%2Asqrt%28171%29 = 26.1534 cm  (rounded)   ANSWER



                    Solution 2


You can apply the intersecting chords theorem - but you should to use it in correct way.

Then two parts of the horizontal chord are x cm each,
while two parts of the vertical chord are 9 cm and 5+14 = 19 cm.


The intersecting chords theorem takes the form

    x*x = 9*19,  or  x^2 = 171,  x = sqrt%28171%29,  PQ = 2x = 2%2Asqrt%28171%29 = 26.1534 cm  (rounded)   ANSWER


giving the same number.

Solved.

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On the intersecting chords theorem,  see the lesson
    - The parts of chords that intersect inside a circle,
in this site.