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| Question 1201734:  The average speed of a car over a certain distance is calculated by dividing the
 total distance travelled by the total time taken. Two towns A and B are 10 km
 apart, A motorist travels from A to B at an average speed of 20 km per hour,
 and travels from B to A at an average 40 km per hour.
 2.3.1 Determine the average speed to the motorist for the two trips
 combined. (i.e. from A to B and the back to A) (6)
 2.3.2 Determine the speed would the motorist have to average on the return trip from
 B to A to yield an overall speed of 30km per hour? Assume the motorist
 has averaged 20km per hour from A to B) (4)
 2.4 AutoZone sells a regular car battery for R 700 and heavy-duty model for
 R1 100. If it sold 40 batteries yesterday for a total of R34 000.
 Indicate how many of each of the type of and indicate the rand the rand value sales of
 each type.
 Answer by mananth(16946)
      (Show Source): 
You can put this solution on YOUR website!  Two towns A and B are 10 km apart, A motorist travels from A to B at an average speed of 20 km per hour,and travels from B to A at an average 40 km per hour. 2.3.1 Determine the average speed to the motorist for the two trips
 combined. (i.e. from A to B and the back to A) (6)
 2.3.2 Determine the speed would the motorist have to average on the return trip from
 B to A to yield an overall speed of 30km per hour? Assume the motorist
 has averaged 20km per hour from A to B) (4)
 
 Two towns A and B are 10 km apart
 speed = 20km/h
 Time taken = d/t = 10/20 = 1/2 hour
 B to A at an average 40 km per hour
 Time taken = 10/40 = 1/4 hour
 Total time = 1/2 +1/4 = 3/4 hour
 Total distance = 10+10 =20 km
 Average speed = 20/(3/4) = 80/3 =26.66 km/h
 Let the return speed be x km/h
 time taken = 10/x
 Total time taken will be (1/2)+(10/x)
 distance = 20 km
 Total average speed required = 30 km/h
 20/((1/2 +10/x ) =30
 20/((x+20)/2x)= 30
 20 * 2x/(x+20) = 30
 40x = 30x +600
 10x = 600
 x= 60 km/h
 
 x	Number of regular batteries sold
 y	Number of  special batteries sold
 
 
 1	x	+	y	=	40
 
 
 700	x	+	1100	y	=	34000	.............2
 Eliminate 	y
 multiply (1)by		-1100
 Multiply (2) by		1
 -1100	x		-1100	y	=	-44000
 700	x		1100	y	=	34000
 Add the two equations
 -400.00	x				=	-10000
 /	-400.00
 x	=	25
 plug value of			x	in (1)
 1.00	x	+		y	=	40
 25.00		+		y	=	40
 y	=	15
 y	=	15
 Ans	x	=	25
 y	=	15
 0	25.00	Number of regular batteries sold
 0	15.00	Number of  special batteries sold
 Rest you can do
 
 
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