SOLUTION: Find the slope of each line. If the line has no slope, say so. y = 3x-2

Algebra ->  Linear-equations -> SOLUTION: Find the slope of each line. If the line has no slope, say so. y = 3x-2      Log On


   

Question 120173This question is from textbook
: Find the slope of each line. If the line has no slope, say so.
y = 3x-2 This question is from textbook

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

the slope_intercept form of a linear equation is : y+=+mx+%2B+b...where m represents a slope, and brepresents y_intercept(or the point where the line crosses y axis)
y+=+3x-2...if you compare this equation to the standard form, you see what m and b are...this is slope_intercept form
slope m+=+3 (rise/run=3)
and b+=+-2.....the line crosses y axis at y=-2
here is detailed explanation with a graph:
Solved by pluggable solver: Graphing Linear Equations
In order to graph y=3%2Ax-2 we only need to plug in two points to draw the line

So lets plug in some points

Plug in x=-2

y=3%2A%28-2%29-2

y=-6-2 Multiply

y=-8 Add

So here's one point (-2,-8)




Now lets find another point

Plug in x=-1

y=3%2A%28-1%29-2

y=-3-2 Multiply

y=-5 Add

So here's another point (-1,-5). Add this to our graph





Now draw a line through these points

So this is the graph of y=3%2Ax-2 through the points (-2,-8) and (-1,-5)


So from the graph we can see that the slope is 3%2F1 (which tells us that in order to go from point to point we have to start at one point and go up 3 units and to the right 1 units to get to the next point) the y-intercept is (0,-2)and the x-intercept is (0.666666666666667,0) ,or (2%2F3,0)


We could graph this equation another way. Since b=-2 this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,-2).


So we have one point (0,-2)





Now since the slope is 3%2F1, this means that in order to go from point to point we can use the slope to do so. So starting at (0,-2), we can go up 3 units



and to the right 1 units to get to our next point


Now draw a line through those points to graph y=3%2Ax-2


So this is the graph of y=3%2Ax-2 through the points (0,-2) and (1,1)