SOLUTION: A shark is swimming 28 feet below sea level. If the angle of depression from a boat on the water to the shark is 19 degrees, what is the horizontal distance between the boat and t

Algebra ->  Trigonometry-basics -> SOLUTION: A shark is swimming 28 feet below sea level. If the angle of depression from a boat on the water to the shark is 19 degrees, what is the horizontal distance between the boat and t      Log On


   

Question 1201702: A shark is swimming 28 feet below sea level. If the angle of depression from a boat on the water to the shark is 19 degrees, what is the horizontal distance between the boat and the shark?
Found 2 solutions by mananth, ikleyn:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
tan+%28theta%29+=+opposite+side+%2Fadjacent+side
tan 19 degrees = 28/x
x = 28/tan 19 degrees
=81.31 ft
81.31 ft
.



Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.

There is such effect as "refraction of light in water",

which changes the entire consideration.


So, if follow right Physics, the solution should be TOTALLY different.