SOLUTION: Find the exact values of sin 2𝜃, cos 2𝜃, and tan 2𝜃 for the given value of 𝜃. cot 𝜃 = 3/4;180° < 𝜃 < 270°

Algebra ->  Trigonometry-basics -> SOLUTION: Find the exact values of sin 2𝜃, cos 2𝜃, and tan 2𝜃 for the given value of 𝜃. cot 𝜃 = 3/4;180° < 𝜃 < 270°      Log On


   



Question 1201599: Find the exact values of sin 2𝜃, cos 2𝜃, and tan 2𝜃 for the given value of 𝜃.
cot 𝜃 = 3/4;180° < 𝜃 < 270°

Answer by ikleyn(52908) About Me  (Show Source):
You can put this solution on YOUR website!
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Find the exact values of sin 2a, cos 2a, and tan 2a for the given value of a.
cot(a) = 3/4;180° < a < 270°.
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Since  180° < a < 270°,  angle  "a"  is in the 3rd quadrant, QIII.

 
From the definition of the cot-function, it is the ratio of the attached leg to the opposite leg.

    So, the attached leg to angle "a" of the right angled triangle is 3 units long horizontally, opposite to x-axis;
        the opposite leg to angle "a" of the right angled triangle is 4 units long vertically,   opposite to y-axis.


The hypotenuse is 5 units long  ( 5 = sqrt%283%5E2%2B4%5E2%29 = sqrt%2825%29 ).


Hence, sin(a) = -4%2F5;  cos(a) = -3%2F5%29.  The signs are  "-",  because we are in QIII.


Therefore

    sin(2a) = 2*sin(a)*cos(a) = 2%2A%28-4%2F5%29%2A%28-3%2F5%29 = 24%2F25.

    cos(2a) = cos%5E2%28a%29-sin%5E2%28a%29 = %28-3%2F5%29%5E2+-+%28-4%2F5%29%5E2 = 9%2F25+-+16%2F25 = -7%2F25.


By the way, it means that angle "2a" is in QII.


Next,  tan(2a) = sin%282a%29%2Fcos%282a%29 = %28%2824%2F25%29%29%2F%28-7%2F25%29%29 = -24%2F7.

Solved.