SOLUTION: A student studying for a vocabulary test knows the meanings of 16 words from a list of 22 words. If the test contains 10 words from the study list, what is the probability that at

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Question 1201520: A student studying for a vocabulary test knows the meanings of 16 words from a list of 22 words. If the test contains 10 words from the study list, what is the probability that at least 8 of the words on the test are words that the student knows? (Round your answer to three decimal places.)
Answer by ikleyn(52799) About Me  (Show Source):
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A student studying for a vocabulary test knows the meanings of 16 words
from a list of 22 words. If the test contains 10 words from the study list,
what is the probability that at least 8 of the words on the test are words
that the student knows? (Round your answer to three decimal places.)
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From the study list of 22 words, the number of tests containing 10 words, is

    C%5B22%5D%5E10 =  = 646646.



The number of test of the length 10, of which the student knows 8 words, is

    C%5B16%5D%5E8%2AC%5B22-16%5D%5E2 = C%5B16%5D%5E8%2AC%5B6%5D%5E2 = 12870*15 = 193050.    (1)

    (each such test is a combination of 8 known words of 16 with 2 added unknown words of 22-16 = 6).



The number of test of the length 10, of which the student knows 9 words, is

    C%5B16%5D%5E9%2AC%5B22-16%5D%5E1 = C%5B16%5D%5E9%2AC%5B6%5D%5E1 = 11440*6 = 68640.      (2)

    (each such test is a combination of 9 known words of 16 with 1 added unknown word of 22-16 = 6).



The number of test of the length 10, of which the student knows 10 words, is

    C%5B16%5D%5E10%2AC%5B22-16%5D%5E0 = C%5B16%5D%5E10%2AC%5B6%5D%5E0 = 8008*1 = 8008.      (3)

    (each such test is a combination of 10 known words of 16 just without any additions).



The total number of favorable tests is the sum of the numbers (1), (2) and (3)

    193050 + 68640 + 8008 = 269698.


Now the probability under the problem's question is

    P = favorable_tests%2Ftotal_tests = 269698%2F646646 = 943%2F2261 = 0.4171  (rounded).    ANSWER

Solved.