SOLUTION: Divide ((3x-2)(x-4)-(x-4)(6-5x))/((4-x)(8x-1))

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Question 1201470: Divide ((3x-2)(x-4)-(x-4)(6-5x))/((4-x)(8x-1))
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
Divide ((3x-2)(x-4)-(x-4)(6-5x))/((4-x)(8x-1))
~~~~~~~~~~~~~~~~~~ 

First, transform the numerator

    (3x-2)(x-4)-(x-4)(6-5x) = (x-4) = (x-4)*(3x+5x -2-6) = (x-4)*(8x-8).


Now divide the numerator by the denominator and cancel the common factor on the way.


You will get the final answer  -%288x-8%29%2F%288x-1%29,  or  -8%2A%28%28x-1%29%2F%288x-1%29%29.


Choose any of the two expressions - they are equivalent.

Done.



Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Divide  ((3x-2)(x-4)-(x-4)(6-5x))/((4-x)(8x-1))


%28%283x+-+2%29%28x+-+4%29-%28x+-+4%29%286+-+5x%29%29%2F%28%284+-+x%29%288x+-+1%29%29 

%28%28x+-+4%29%28%283x+-+2%29+-+%286+-+5x%29%29%29%2F%28%284+-+x%29%288x+-+1%29%29 ----- Factoring out GCF, x - 4, in numerator

%28%28x+-+4%29%283x+-+2+-+6+%2B+5x%29%29%2F%28%284+-+x%29%288x+-+1%29%29

%28%28x+-+4%29%288x+-+8%29%29%2F%28%284+-+x%29%288x+-+1%29%29

%28-+1%284+-+x%29%288x+-+8%29%29%2F%28%284+-+x%29%288x+-+1%29%29 = %28-+1cross%28%284+-+x%29%29%288x+-+8%29%29%2F%28cross%28%284+-+x%29%29%288x+-+1%29%29 = highlight_green%28-+%28%288x+-+8%29%29%2F%28%288x+-+1%29%29%29