SOLUTION: You are going to draw 3 balls from the sack containing, 7 red balls,5 green balls, and 4 blue balls. If you REPLACE THE BALLS AFTER EACH DRAWING, what is the probability of drawing
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-> SOLUTION: You are going to draw 3 balls from the sack containing, 7 red balls,5 green balls, and 4 blue balls. If you REPLACE THE BALLS AFTER EACH DRAWING, what is the probability of drawing
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Question 1201421: You are going to draw 3 balls from the sack containing, 7 red balls,5 green balls, and 4 blue balls. If you REPLACE THE BALLS AFTER EACH DRAWING, what is the probability of drawing:
a) All red balls?
b) All green balls?
c) All blue balls?
d) A red ball, a blue ball and a green ball in THAT ORDER?
e) A red ball, a blue ball and a green ball in ANY ORDER? Answer by ikleyn(52776) (Show Source):
You can put this solution on YOUR website! .
You are going to draw 3 balls from the sack containing, 7 red balls,5 green balls, and 4 blue balls.
If you REPLACE THE BALLS AFTER EACH DRAWING, what is the probability of drawing:
a) All red balls?
b) All green balls?
c) All blue balls?
d) A red ball, a blue ball and a green ball in THAT ORDER?
e) A red ball, a blue ball and a green ball in ANY ORDER?
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Total balls is 7 + 5 + 4 = 16.
(a) P = = .
(b) P = = .
(c) P = = = .
(d) P = = reduce it.
(e) P = = reduce it.
Here 6 = 1*2*3 is the number of all possible permutations of 3 items.
