SOLUTION: If you are going to be drawing 3 balls from a sack containing 4 red balls, 3 green balls and 6 blue balls. If you DO NOT REPLACE the balls after each drawing, what is the probabili
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-> SOLUTION: If you are going to be drawing 3 balls from a sack containing 4 red balls, 3 green balls and 6 blue balls. If you DO NOT REPLACE the balls after each drawing, what is the probabili
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Question 1201418: If you are going to be drawing 3 balls from a sack containing 4 red balls, 3 green balls and 6 blue balls. If you DO NOT REPLACE the balls after each drawing, what is the probability of drawing:
a) all red balls?
b) all green balls?
c) all blue balls?
d) A red ball, a blue ball and a green ball in that order?
e) A red ball, a blue ball and a green ball in any order? Answer by ikleyn(52756) (Show Source):
Total balls is 4 + 3 + 6 = 13.
(a) P = = = = reduce this fraction.
(b) P = = = reduce this fraction.
(c) P = = = reduce this fraction.
(d) P = = reduce it.
(e) P = = reduce it.
Here 6 = 1*2*3 is the number of all possible permutations of 3 items.
I answered all your questions.
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