| 
 
 
| Question 1201103:  According to the U.S. Census Bureau, the population of the United States in 2008 was 304 million people. In addition, the population of the United States was growing at a rate of 1.1% per year. Assuming this growth rate is continues, the model
 P(t)=304*(1.011)^t-2008
 represents the population P (in millions of people) in year t.
 According to the model, when will the population be 412 million people? Be sure to round your answer to the nearest whole year.
 Year _____
 
 Answer by Theo(13342)
      (Show Source): 
You can put this solution on YOUR website! population in 2008 = 304 million. formula is f = p * (1+r) ^ n
 when r = .011 (1.1%), the formula bcomes:
 f = 304 * 1.011 ^ n
 n is the number of years from 2008.
 when f = 412 million, the formula becomes:
 412 = 304 * 1.011 ^ n
 divide both sides of the equation by 304 to get:
 412/304 = 1.011 ^ n
 take the log of both sides of this equation to get:
 log(412/304) = log(1.011 ^ n)
 by log rule that says log(b^n) = n * log(b), this becomes:
 log(412/304) = n * log(1.011)
 solve for n to get:
 n = log(412/304) / log(1.011) = 27.78768868.
 replace n in the original equation with that and solve for f to get:
 f = 304 * 1.011 ^ 27.78768868 = 412.
 this confirms the value of n is correct.
 the population will grow to 412 million in 27.78768868 years after the end of 2008.
 that would make it at the end of 2008 + that = at the end of 2035.787689.
 that would be in the year 2036.
 at the end of 2035, the population will be 304 * 1.011 ^ (2035 - 2008) = 408.4649392.
 at the end of 2036, the population will be 304 * 1.011 ^ (2036 - 2008) = 412.9580535.
 it becomes 412 some time between the end of 2035 and the end of 2036.
 
 | 
  
 | 
 |