SOLUTION: on a trip jennifer noticed that her car averaged 21 mi/gal of gas except for the days she used the air conditioning, and then it averaged only 17 mi/gal. if she use 91 gal of gas t

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Question 1201011: on a trip jennifer noticed that her car averaged 21 mi/gal of gas except for the days she used the air conditioning, and then it averaged only 17 mi/gal. if she use 91 gal of gas to drive 1751 mi, on how many of those miles did she used the air conditioning?

Answer by ikleyn(52784) About Me  (Show Source):
You can put this solution on YOUR website!
.
on a trip jennifer noticed that her car averaged 21 mi/gal of gas except
for the days she used the air conditioning, and then it averaged only 17 mi/gal.
if she use 91 gal of gas to drive 1751 mi, on how many of those miles
did she used the air conditioning?
~~~~~~~~~~~~~~~~~~

Let x be the miles where she used the air conditioning.

Then miles where she didn't use the air conditioning were (1751-x).


Now we can write this equation for the total gas spent

    x%2F21 + %281751-x%29%2F17 = 91 gallons of gas (total).    (*)


    +------------------------------------------------+
    |    At this point, the setup is just complete,  |
    |    and our task is to solve this equation.     |
    +------------------------------------------------+


For it, multiply both sides by 21*17.  You will get

    17x + 21*(1751-x) = 91*21*17

    17x + 21*1751 - 21x = 32487

    17x - 21x = 32487 - 21*1751

       -4x    =    -4284

         x    =    %28-4284%29%2F%28-4%29 = 1071.


ANSWER.  She used the air conditioning on 1071 miles.


CHECK.  I will check if equation (*) is held.

        1071%2F21 + %281751-1071%29%2F17 = 51 + 40 = 91 gallon of gas, in total.   ! Correct !

Solved.