SOLUTION: In a batch of 100 CDs 6 are defective. A sample of three Cds is to be selected at random. What is the probability that two of the three Cds will be defective

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Question 1200689: In a batch of 100 CDs 6 are defective. A sample of three Cds is to be selected at random. What is the probability that two of the three Cds will be defective
Answer by ikleyn(52915) About Me  (Show Source):
You can put this solution on YOUR website!
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The number of all possible triples from 100 CDs is  

    C%5B100%5D%5E3 = %28100%2A99%2A98%29%2F%281%2A2%2A3%29 = 161700.


The number of triples CDs, that contain exactly 2 of 6 defective CDs is 

    C%5B6%5D%5E2%2AC%5B94%5D%5E1 = 15*94 = 1410.


The desired probability is the ratio of these numbers

    P = 1410%2F161700 = 0.00872   (rounded).    ANSWER

Solved.