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Question 1200528: Weather balloons are filled with hydrogen and released at various sites to measure and transmit data about conditions like air pressure and temperature. initially, the balloon reports an internal volume of 2,144.0 cubic feet and is floating at a constant temperature and atmospheric pressure. Fifteen seconds later, the balloon reports that it is losing volume and has a reduced volume of 2,139.8 cubic feet.
a. Using the given information, list two points that represent the relationship of time to volume.
b. Determine the average rate at which the balloon is losing volume.
c. Write the function V(t) that models the volume of the balloon. Let t represent the time in seconds.
d. What will the volume be after 5 minutes?
e. Determine how long in minutes it will take the volume of the balloon to reach a volume of 10 cubic feet.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Weather balloons are filled with hydrogen and released at various sites to measure and transmit data about conditions like air pressure and temperature. initially, the balloon reports an internal volume of 2,144.0 cubic feet and is floating at a constant temperature and atmospheric pressure. Fifteen seconds later, the balloon reports that it is losing volume and has a reduced volume of 2,139.8 cubic feet.
a. Using the given information, list two points that represent the relationship of time to volume.
Time Volume
0 2144
15 2139.8
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b. Determine the average rate at which the balloon is losing volume.
(2144 - 2139.8)/15 cubic ft per second
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c. Write the function V(t) that models the volume of the balloon. Let t
represent the time in seconds.
V(t) = -r*t (r is the rate from b.
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d. What will the volume be after 5 minutes?
5 minutes = 300 seconds
V(t) = -r*t (r is the rate from b.
Find v(300)
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e. Determine how long in minutes it will take the volume of the balloon to reach a volume of 10 cubic feet.
V(t) = -r*t (r is the rate from b.
V(t) = 2144 -r*t = 10
Solve for t
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