SOLUTION: A certain two-digit number has a value that that is three times the sum of its digits. The units digit is one more than three times the tens digit. Find the number.
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Question 120050: A certain two-digit number has a value that that is three times the sum of its digits. The units digit is one more than three times the tens digit. Find the number.
Help me, please. I honestly would have tried if I understood the question. Help me! Thanks in advanced!! :) -- Rae. Found 2 solutions by checkley71, stanbon:Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! 10x+y=3(x+y)
y=3x+1
10x+(3x+1)=3x+3(3x+1)
10x+3x+1=3x+9x+3
13x+1-12x-3=0
x-2=0
x=2 answer for the tens digit.
y=3*2+1
y=6+1
y=7 units digit.
proof
27=3(2+7)
27=3*9
27=27
You can put this solution on YOUR website! A certain two-digit number has a value that that is three times the sum of its digits. The units digit is one more than three times the tens digit. Find the number.
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Let the number be 10t+u where t is the tens digit and u is the units digit.
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EQUATION:
10t+u = 3(t+u)
u = 3t+1
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Rearrange the equations:
7t = 2u
u = 3t+1
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Substitute to solve for "t":
7t = 2(3t+1)
t = 2
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Substitute to solve for "u":
u = 3*2+1 = 7
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The number is 27
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Cheers,
Stan H.
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