SOLUTION: A car travels from town P for 50km due
North to town Q. It then travels 80km on
bearing of 270° to town R. Find: (a) The
shortest distance from town P to town R
(b) The bearin
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-> SOLUTION: A car travels from town P for 50km due
North to town Q. It then travels 80km on
bearing of 270° to town R. Find: (a) The
shortest distance from town P to town R
(b) The bearin
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Question 1200469: A car travels from town P for 50km due
North to town Q. It then travels 80km on
bearing of 270° to town R. Find: (a) The
shortest distance from town P to town R
(b) The bearing of town R from P (c) bearing
of P from R.
You can put this solution on YOUR website! A car travels from town P for 50km due
North to town Q. It then travels 80km on
bearing of 270° to town R. Find: (a) The
shortest distance from town P to town R
(b) The bearing of town R from P (c) bearing
of P from R.
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a) It's a right triangle with sides of 50 and 80
d^2 - 50^2 + 80^2 = 8900
d = ~94.34 km
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b) & c)
tan(P) = 80/50
P = 58 degs
Bearing form P to R = 302 degs
Bearing from R to P = 360 - 302 = 058 degs
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