SOLUTION: or another subject ( a 29yr old male) in the study by Diskin et al (A-10), acetone levels were normally distributed with a mean of 870 and a standard deviation of 211ppb. Find th

Algebra ->  Probability-and-statistics -> SOLUTION: or another subject ( a 29yr old male) in the study by Diskin et al (A-10), acetone levels were normally distributed with a mean of 870 and a standard deviation of 211ppb. Find th      Log On


   



Question 1200240: or another subject ( a 29yr old male) in the study by Diskin et al (A-10), acetone levels were
normally distributed with a mean of 870 and a standard deviation of 211ppb. Find the
probability that on a given day the subject’s acetone level is ;
a) Between 600 and 1000 ppb
b) Over 900 ppb
c) Under 500ppb
d) Between 900 and 1100ppb

Answer by ikleyn(52877) About Me  (Show Source):
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.
or another subject ( a 29yr old male) in the study by Diskin et al (A-10), acetone levels were
normally distributed with a mean of 870 and a standard deviation of 211ppb. Find the
probability that on a given day the subject’s acetone level is ;
a) Between 600 and 1000 ppb
b) Over 900 ppb
c) Under 500ppb
d) Between 900 and 1100ppb
~~~~~~~~~~~~~~~~~~

Each probability in this problem is the area under the normal curve 
     between the assigned marks (cases (a) and (d)), 
     or to the left  of the mark (case (c))
     or to the right of the mark (case (b)).


Use function normalcdf of your calculator. 

normalcdf is the  " Normal Cumulative distribution function ".

The format of this function is normalcdf(low mark, high mark, mean, SD).


(a)  P = normalcdf(600, 1000, 870, 211).


(b)  P = normalcdf(900, 9999, 870, 211).


(c)  P = normalcdf(-9999, 500, 870, 211).


(d)  P = normalcdf(900, 1100, 870, 211).

Your job now is to press buttons on your calculator :   right buttons in the right order.


If you need instructions on using your calculator for normalcdf function,
find all necessary instructions from this video-lesson

Normal Distribution: Calculating Probabilities {TI 84 Plus CE}
https://www.youtube.com/watch?v=IyEKEL9nm28

or from this textual description
https://cosmosweb.champlain.edu/people/stevens/WebTech/TIFiles/Chap6-TI-83.pdf