SOLUTION: In 1998, the sum of the number of $2 bills in circulation and the number of $50 bills in circulation was 1,500,888,647. The number of $50 bills was 366,593,903 more than the number

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: In 1998, the sum of the number of $2 bills in circulation and the number of $50 bills in circulation was 1,500,888,647. The number of $50 bills was 366,593,903 more than the number      Log On


   



Question 1200191: In 1998, the sum of the number of $2 bills in circulation and the number of $50 bills in circulation was 1,500,888,647. The number of $50 bills was 366,593,903 more than the number of $2 bills. Write a system of equations to represent this situation.
Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

Answer:
system%28%0D%0Ax%2By+=+1500888647%2C%0D%0Ay+=+x%2B366593903%0D%0A%29
x = number of $2 bills
y = number of $50 bills


Explanation:
The expression x+y is the total of number of $2 or $50 bills. This total is set equal to the 1,500,888,647 (roughly 1.5 billion) mentioned. This is how the first equation was set up.

The second equation is from the fact "The number of $50 bills was 366,593,903 more than the number of $2 bills"