SOLUTION: Randy has a handful of dimes and nickels valuing $4.15.He has 7 more dimes than he has nickels.How many of each coin does he have?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Randy has a handful of dimes and nickels valuing $4.15.He has 7 more dimes than he has nickels.How many of each coin does he have?      Log On


   

Question 1200174: Randy has a handful of dimes and nickels valuing $4.15.He has 7 more dimes than he has nickels.How many of each coin does he have?
Answer by ikleyn(52903) About Me  (Show Source):
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Randy has a handful of dimes and nickels valuing $4.15.
He has 7 more dimes than he has nickels. How many of each coin does he have?
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There are  x nickels  and  (x+7)  dimes.


The total money equation is

    5x + 10*(x+7) = 415  cents.


Simplify this equation and find x

    5x + 10x + 70 = 415

      15x         = 415 - 70 

      15x         =    345

        x         =    345/15 = 23.


ANSWER.  23 nickels and 30 dimes.


CHECK.  23*5 + 30*10 = 115 + 300 = 415 cents.  ! correct !

Solved.