SOLUTION: Evaluate limit (as x approaches to 2-) tan^-1 ((x^2-5/(6-3x)) tan^-1 = tan inverse

When x approaches to  2-,  the numerator tends to  2^2-5 = -1;

while the denominator tends to 0, remaining positive.


Thus the ratio    tends to  -oo (minus infinity).


Hence, tan^-1(...)  tends to .    ANSWER