SOLUTION: a body b is dropped from the top of the tower 100m high at the same instant that a body a is thrown vertically upward from the ground. the two bodies pass each other at a height of

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Question 1200071: a body b is dropped from the top of the tower 100m high at the same instant that a body a is thrown vertically upward from the ground. the two bodies pass each other at a height of 21.6m from the ground.
a. Initial velocity og body A?
b. Maximum height of body A?
C. Final velocity of body B?

Answer by ikleyn(52834) About Me  (Show Source):
You can put this solution on YOUR website!
.
a body B is dropped from the top of the tower 100m high.
at the same instant that a body A is thrown vertically upward from the ground.
the two bodies pass each other at a height of 21.6m from the ground.
a. Initial velocity og body A?
b. Maximum height of body A?
C. Final velocity of body B?
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The falling body B height equation is

    h = -4.9%2At%5E2+%2B+100


Use it to find the time "t", when it reaches the height 21.6m

    -4.9t%5E2+%2B+100 = 21.6

    4.9t%5E2 = 100 - 21.6

    t = sqrt%28%28100-21.6%29%2F4.9%29 = 4 seconds.


For the body A thrown vertically upward from the ground, the height equation is

    h = -4.9t%5E2+%2B+vt,

where v is the unknown vertical initial velocity.  We just know that this body reached 
the height 21.6 meters in 4 seconds; so

    21.6 = -4.9%2A4%5E2+%2B+v%2A4.


Solve this equation to find v

    v = %2821.6+%2B+4.9%2A4%5E2%29%2F4 = 25 m/s.


It is the answer to question (a): the initial velocity of body A is 25 m/s.