SOLUTION: a body b is dropped from the top of the tower 100m high at the same instant that a body a is thrown vertically upward from the ground. the two bodies pass each other at a height of
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Question 1200071: a body b is dropped from the top of the tower 100m high at the same instant that a body a is thrown vertically upward from the ground. the two bodies pass each other at a height of 21.6m from the ground.
a. Initial velocity og body A?
b. Maximum height of body A?
C. Final velocity of body B? Answer by ikleyn(52834) (Show Source):
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a body B is dropped from the top of the tower 100m high.
at the same instant that a body A is thrown vertically upward from the ground.
the two bodies pass each other at a height of 21.6m from the ground.
a. Initial velocity og body A?
b. Maximum height of body A?
C. Final velocity of body B?
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The falling body B height equation is
h =
Use it to find the time "t", when it reaches the height 21.6m
= 21.6
= 100 - 21.6
t = = 4 seconds.
For the body A thrown vertically upward from the ground, the height equation is
h = ,
where v is the unknown vertical initial velocity. We just know that this body reached
the height 21.6 meters in 4 seconds; so
21.6 = .
Solve this equation to find v
v = = 25 m/s.
It is the answer to question (a): the initial velocity of body A is 25 m/s.